BaseX-Talk November 2017

basex-talk@mailman.uni-konstanz.de

27 participants
44 discussions

Re: [basex-talk] Rounding/parsing decimal vs float
by Kristian Kankainen 01 Nov '17

01 Nov '17

You need to use xs:float or xs:double instead of xs:decimal to be able to use the 'e' or 'E' as the exponent separator. Br, Kristian K1. nov 2017 13:18 kirjutas kuupäeval Marco Lettere <m.lettere(a)gmail.com>: > > Hi all, > > I thought of asking this in parallel of hacking my own parsing procedure > ... > > Is there a native way to parse scientific notation string into > xs:decimal since a direct casting (xs:decimal("1e1")) is not allowed? > > Thanks, > > Marco. >

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Rounding/parsing decimal vs float
by Marco Lettere 01 Nov '17

01 Nov '17

Hi all, I thought of asking this in parallel of hacking my own parsing procedure ... Is there a native way to parse scientific notation string into xs:decimal since a direct casting (xs:decimal("1e1")) is not allowed? Thanks, Marco.

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Flexible update via function
by michael4you＠arcor.de 01 Nov '17

01 Nov '17

Hello, How to add/replace a complete node in a node tree, with done by a function and by according function parameters. That means with flexible instructions. Such as: declare function local:NodeAdd($XML, $XMLPath, $XMLValue) { ?? }; let $XML := <root><xml>text</xml></root> let $XMLAdd := <B>BBB</B> let $XMLPath := $XML/xml return local:NodeAdd($XML, $XMLPath , $XMLAdd) Problem: Following examples didn't work, because an internal reference to copy-XML-structure is needed/forced. example 1: copy / modify declare function local:NodeAdd($XML, $XMLPath, $XMLValue) { copy $XML2 := $XML modify ( insert node $XMLValue into $XML2/xml ) return $XML2 }; But: Instead of into $XML2/xml, into $XML/xml is needed, respectively into $XMLPath Thanks a lot Michael

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UnaryLookup expression failure
by Gunther Rademacher 01 Nov '17

01 Nov '17

While testing some XQuery lookup expressions on BaseX 8.6.7, I got a wrong result for this one: (map{'a':(1,3)},map{'a':(2,4)})!?a[2] It should have returned the second item of the 'a' entry for each of the maps, i.e. 3 4 but it returns just 3 Apparently the predicate is applied as if everything before it was in parentheses, i.e. as if it were ((map{'a':(1,3)},map{'a':(2,4)})!?a)[2] The (simplified) parse tree for the original expression and the XQuery 3.1 grammar however indicates that the predicate is part of the mapping target expression: <SimpleMapExpr> <ParenthesizedExpr> ... </ParenthesizedExpr> <TOKEN>!</TOKEN> <PostfixExpr> <UnaryLookup> <TOKEN>?</TOKEN> <NCName>a</NCName> </UnaryLookup> <Predicate> <TOKEN>[</TOKEN> <IntegerLiteral>2</IntegerLiteral> <TOKEN>]</TOKEN> </Predicate> </PostfixExpr> </SimpleMapExpr> Best regards Gunther

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BaseX-Talk November 2017