Re: [basex-talk] Sequence comparison

Am 25.11.2020 um 06:37 schrieb Giuseppe G. A. Celano:

I have to compare two sequences and find common items, irrespective of their positions:

for $a  in (1,2,3,5,3) for $u  in (1,3,2,3) where $a = $u group by $o := $a return <c>{$a}</c>

This returns <c>1</c> <c>2</c> <c>3 3 3 3</c>

I would like 3 to be repeated only twice (i.e., each item in the first sequence should pair only with one in the second sentence): is there an XQuery "trick" for that in the FLOWR expression?

I think

for $a in (1,2,3,5,3)[. = (1,3,2,3)] group by $o := $a return <c>{$a}</c>

would do that