Re: [basex-talk] Fwd: Re: How to process very long node sequences

Hi Hans-Jürgen,

for $node at $pos in doc('otds-fti')/foo/bar/document{.}
return ...

So the final step /document{.}

turns the for loop into caching.

A minor thing I'd like to add:

* The semantics of the path expression is that all results need to be returned in "document order". * Document order is well-defined within a single document. However, it is implementation-defined when working across multiple documents. * As a result, the following query...

let $doc1 := document { 'a' } let $doc2 := document { 'a' } return ($doc1, $doc2)/self::node()

…may either return doc1 or doc2 as first result.

The nodes won't be reordered with the simple map operator:

for $node at $pos in doc('otds-fti')/foo/bar ! document{.}

Cheers, Christian