Re: [basex-talk] relative path between two element in xquery

Hey Rob,

In my lib I have a function that protects all regexp special characters. Maybe a bit too much heavy machinery for what it does but it works ;-) I gladly receive improvements.

declare function route:re-escape($string as xs:string) as xs:string { let $regexp-chars := ('.','*','+','|','?','(',')','[',']','{','}','^') return (: Note that '' and '$' in the fold caused invalid pattern errors therefore put them in separate replace :) fold-left( $regexp-chars, replace(replace($string, '\', '\\'), '$', '\$'), function($a, $b) { replace($a, ''||$b, '\'||$b ) } ) };

--Marc

On Fri, Aug 15, 2014 at 11:55 AM, Rob Stapper r.stapper@lijbrandt.nl wrote:

Hi,

How can I construct the relative path between two elements in an xml-file.

Most probably overlooking the obvious I ended up with the solution below, which, unfortunately, triggers an runtime-error.

My not-working solution:

let $xml :=

<xml>

<A>

  <B/>

</A>

</xml>

let $b := $xml//B

let $a := $xml//A

return replace( string( path( $b))

                         , string( path( $a))

                         , ''

                        )

Two questions:

•      How to retrieve the relative path between two element within a
  

xml-file?

•      Why does the solution above trigger an error? Can it be a bug?
  

( oops, three questions)

Thnx in advance for the reply,

Rob Stapper

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