I am happy to be corrected.
Cheers,
E. ---- Eliot Kimber, Owner Contrext, LLC http://contrext.com
On 7/29/15, 10:42 AM, "Florent Georges" <fgeorges@gmail.com on behalf of lists@fgeorges.org> wrote:
Hi,
That would base the type annotation on the lexical value. For instance, the string '0' would be labelled as "integer" (given you test for xs:integer before xs:string):
let $var := '0' return if ( $var castable as xs:integer ) then 'integer' else if ( $var castable as xs:string ) then 'string' else 'unknown type' (: -> 'integer' :)
The operator "instance of" would solve that problem. But then, for that purpose, there is the "typeswitch" instruction:
typeswitch ( '0' ) case xs:integer return 'integer' case xs:string return 'string' default return 'unknown type' (: -> 'string' :)
Regards,
-- Florent Georges http://fgeorges.org/ http://h2oconsulting.be/
On 29 July 2015 at 17:34, Eliot Kimber ekimber@contrext.com wrote:
I believe you need to use the "castable as" or "instance of" operators to determine the type, e.g.:
let $typeName := if ($somevar castable as xs:integer) then 'integer' else if ($somevar castable as xs:string) then 'string' else 'unknown type'
Or something close to that. There is also "instance of", which might be
I also found this paper, which might be interesting:
http://www.balisage.net/Proceedings/vol8/html/Holstege01/BalisageVol8-Hol st ege01.html
Cheers,
E.
Eliot Kimber, Owner Contrext, LLC http://contrext.com
On 7/29/15, 9:54 AM, "Rob Stapper" <basex-talk-bounces@mailman.uni-konstanz.de on behalf of r.stapper@lijbrandt.nl> wrote:
Hello,
I must be overlooking something, so excuses in advance, but: How can I retrieve the datatype of a variable?
TIA, Rob Stapper
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