Re: [basex-talk] Joining a varying number of information sources (with XQuery)?

Here's one thing you may be asking - do you want to know how to specify a join for n sources?

Yes. ‒ Your enquiry points into a direction for which I am looking also for further solution ideas.

for $e in $eng for $d in $deu for $u in $ukr for $h in $heb where $e/@n = $d/@n   and $e/@n = $u/@n   and $e/@n = $h/@n return   <wf>{ $e, $d, $u, $h }</wf>

Will any improvements become relevant for the specification of such join conditions?

Regards, Markus