Hi Ben,

Am Mon, Feb 14, 2022 at 03:53:40PM +0100 schrieb Ben Engbers:

I have 2 questions: 1: Is it possible to use separate counters for the inner and the outer loop? (How should I define the $countInner?)

I learned about the `count` feature just from your example. It does not seem to do what you want; I would try the "at" in a "for" loop.

2: How can I formulate the query for getting the correct output?

Your example is not well-formed, you're probably missing a closing </spreekbeurt> in the second <handeling> around the second <spreker>.

Anyway, I think what you want is to iterate over $Turn//spreker/text(), not just use the entire sequence. Here's how I transformed your first query (I stored your example in a variable called $file for experimentation):

let $Blogs := $file let $Turns := $file

for $Blog in $file, $Turn in $file where $Turn//datum/@date = $Blog//datum/@date order by $Blog//datum/@date count $Count let $Id := $Blog/handeling/@id let $Datum := $Blog//datum/@date for $Speaker at $ct in $Turn//spreker/text() return($Id, $Datum, $Speaker, $Count, $ct)

I think you can work towards your desired output format from there.

Hope this helps, Sebastian

On 14.02.2022 15:53, Ben Engbers wrote:

Hi,

I have a collection of 740 XML-documents which I want to flatten. The files all have the same structure:

<handeling id="h_1">   <datum date="d_1"/>   <spreekbeurt><spreker>spreker_1</spreker></spreekbeurt>   <spreekbeurt><spreker>spreker_3</spreker></spreekbeurt> </handeling>

<handeling id="h_2">   <datum date="d_2"/>   <spreekbeurt> <spreker>spreker_2</spreker></spreekbeurt><spreekbeurt> <spreker>spreker_1</spreker><spreekbeurt> <spreker>spreker_4</spreker></spreekbeurt> </handeling>

<handeling id="h_3">   <datum date="d_3"/>   <spreekbeurt><spreker>spreker_2</spreker></spreekbeurt>   <spreekbeurt><spreker>spreker_3</spreker></spreekbeurt>   <spreekbeurt><spreker>spreker_2</spreker></spreekbeurt>   <spreekbeurt><spreker>spreker_1</spreker></spreekbeurt> </handeling>

The following query gives this result: import module namespace  functx = "http://www.functx.com";

let $Blogs := collection("Blog") let $Turns := collection("Blog")

for $Blog in collection("Blog"),     $Turn in collection("Blog")     where $Turn//datum/@date = $Blog//datum/@date     order by $Blog//datum/@date     count $Count   let $Id := $Blog/handeling/@id   let $Datum := $Blog//datum/@date

let $Speaker := $Turn//spreker/text()

return($Id, $Datum, $Speaker, $Count)

id="h_1" date="d_1" spreker_1 spreker_3 1 id="h_2" date="d_2" spreker_2 spreker_1 spreker_4 2 id="h_3" date="d_3" spreker_2 spreker_3 spreker_2 spreker_1 3

But what I eventually need is this (for clarity shown as a table):

1, id="h_1", date="d_1", 1, spreker_1 1, id="h_1", date="d_1", 2, spreker_3 2, id="h_2", date="d_2", 1, spreker_2 2, id="h_2", date="d_2", 2, spreker_1 2, id="h_2", date="d_2", 3, spreker_4 3, id="h_3", date="d_3", 1, spreker_2 3, id="h_3", date="d_3", 2, spreker_3 3, id="h_3", date="d_3", 3, spreker_2 3, id="h_3", date="d_3", 4, spreker_1

It seem you want to process each document to generate that first number (e.g. 1, 2, 3) and then "inside" your want to process each "spreker" element.

Your shown example data doesn't seem to suggest you need to use any joins on the two collections as you seem to process the same collection("Blog") anyway so why does

for $Blog in collection("Blog") order by $Blog//datum/@date let $Id := $Blog/handeling/@id let $Datum := $Blog//datum/@date count $countOuter

for $speaker at $pos in $Blog//spreker/string()

return ($countOuter, $Id, $Datum, $pos, $speaker)

suffice, or, as a "table",

string-join( for $Blog in collection("Blog") order by $Blog//datum/@date let $Id := $Blog/handeling/@id let $Datum := $Blog//datum/@date count $countOuter

for $speaker at $pos in $Blog//spreker/string()

return string-join(($countOuter, $Id, $Datum, $pos, $speaker), ', ') , '&#10;')