Thanks for your answer.

I may be wrong, but for me uri (namespace) and prefix are not necessarily the same. So, I would expect always a prefixed name for @name, because when uri and prefix are different, it becomes impossible to deduce the prefixed name.

But it may need a closer look to the specification.

Best regards, Emmanuel

Le 24 févr. 2015 à 17:28, Christian Grün christian.gruen@gmail.com a écrit :

Hi Emmanuel,

I think the current behavior is correct. You'll indeed need to look at both the name and uri in order to reference the correct function. I just tried the following query:

declare default function namespace 'x'; declare namespace x='x'; declare function a() { 1}; declare function x:b() { 1}; declare function Q{x}c() { 1}; for $f in (a#0, x:b#0, Q{x}c#0) return inspect:function($f)/@name/fn:string()

It returns the following result:

<function name="a" uri="x"> <return type="xs:integer"/> </function> <function name="x:b" uri="x"> <return type="xs:integer"/> </function> <function name="c" uri="x"> <return type="xs:integer"/> </function>

Do you have another example to indicate what you are expecting in the result?

Thanks, Christian

I’m trying an exemple below, but after a closer look, everything is alright. I was confused by QNames construction…

If we had two different modules.

In the first one

module namespace x = ‘x' ; declare default function namespace 'x'; declare function a() { 1}; declare function x:b() { 1}; declare function Q{x}c() { 1}; for $f in (a#0, x:b#0, Q{x}c#0) return inspect:function($f)/@name/fn:string()

In an other one

module namespace y = ‘y' ; declare function y:a() { 1}; declare function y:b() { 1}; declare function Q{y}c() { 1}; for $f in (a#0, y:b#0, Q{y}c#0) return inspect:function($f)/@name/fn:string()

And we would like to retrieve the QName of the function called « a » in the context, the one that exists in the module x if it exists and, if it doesn’t exists, the one in the module y :

let $context := inspect:context()//function[@name = ‘a’] return if( $context[@uri = ‘x'] ) then xs:QName($context/@uri/fn:string || : || $context/@name/fn:string) else if( $context[@uri = ‘y’] ) then xs:QName($context/@uri/fn:string || : || $context/@name/fn:string) else ’something else'

There would be an issue if we wanna built a QName with xs:QName. But I think it could be OK if we were building a QName with fn:QName because the name is optionally prefixed with fn:QName ( fn:QName( $context/@uri/fn:string, $context/@name/fn:string) )

So, in fact, everything is all right.

Thanks a lot,

Emmanuel

Le 24 févr. 2015 à 18:19, Christian Grün christian.gruen@gmail.com a écrit :

...

I may be wrong, but for me uri (namespace) and prefix are not necessarily the same. So, I would expect always a prefixed name for @name, because when uri and prefix are different, it becomes impossible to deduce the prefixed name.

I see (I guess).. Could you provide us with some example code that demonstrates the confusion? Christian

...

But it may need a closer look to the specification.

Best regards, Emmanuel

...

Le 24 févr. 2015 à 17:28, Christian Grün christian.gruen@gmail.com a écrit :

Hi Emmanuel,

I think the current behavior is correct. You'll indeed need to look at both the name and uri in order to reference the correct function. I just tried the following query:

declare default function namespace 'x'; declare namespace x='x'; declare function a() { 1}; declare function x:b() { 1}; declare function Q{x}c() { 1}; for $f in (a#0, x:b#0, Q{x}c#0) return inspect:function($f)/@name/fn:string()

It returns the following result:

<function name="a" uri="x"> <return type="xs:integer"/> </function> <function name="x:b" uri="x"> <return type="xs:integer"/> </function> <function name="c" uri="x"> <return type="xs:integer"/> </function>

Do you have another example to indicate what you are expecting in the result?

Thanks, Christian